What is the half-life for the alpha decay of U 238?
Half life of Uranium-238 is 4.468 x 109 years. Approximately the age of the earth. As the number of neutrons in the nucleus changes up or down from the stable number(s) the nucleus becomes more and more unstable. An unstable nucleus emits some particle to move toward a stable configuration.
What is the end product of the decay of uranium-238?
A nucleus of uranium-238 decays by alpha emission to form a daughter nucleus, thorium-234. This thorium, in turn, transforms into protactinium-234, and then undergoes beta-negative decay to produce uranium-234.
What is the decay equation for alpha decay?
In the alpha decay of U238 (Equation 17.3. 1), both atomic and mass numbers are conserved: mass number: 238=4+234. atomic number: 92=2+90.
What is the nuclear equation for the alpha decay of thorium 232?
The nucleus that decays is called the “parent” and the one that it tranforms into is called the “daughter.” Here are examples of alpha decay that you will find in your text. 90-Th-232 —> 88-Ra-228 + 2-He-4.
How do you do alpha decay problems?
So first look at the father nucleus and list its number of protons and its atomic weight. Step 3) Now from number of neutrons subtract 2 and from number of protons subtract 2 as an alpha particle has 2 neutrons and 2 protons and in an alpha decay an alpha particle will always form in case of any any father nucleus.
What is the nuclear equation for the alpha decay of Rn 222?
Radon-222 has an atomic number (Z) of 86 so an atom of radon-222 contains 86 protons in its nucleus. We now have a description of the particle lost as a nucleus that contains 4 nucleons, two of the nucleons are protons….Alpha Decay.
What happens when uranium-238 breaks down?
The half-life of uranium-238 is 4.5 billion years. It decays into radium-226, which in turn decays into radon-222. Radon-222 becomes polonium-210, which finally decays into a stable nuclide, lead.
When U-238 undergoes radioactive decay by losing an alpha particle The other product is?
A nucleus of uranium-238 (the parent nuclide) undergoes α decay to form thorium-234 (the daughter nuclide).
When U-238 decays by emitting an alpha particle What is the atomic number of the resulting nucleus What is the resulting atomic mass?
Explanation: Uranium-238 produces thorium-234 by alpha decay. An α-particle is a helium nucleus. It contains 2 protons and 2 neutrons, for a mass number of 4.
What element would be formed if thorium 230 undergoes alpha decay?
A. The nuclide thorium-230 undergoes alpha emission to give radium-226 .
What element will be formed if thorium-230 undergoes alpha decay?